Hello,
I’m trying to use Validator in my PHP/CodeIgniter web app.
In my code, I have:
<form action=".../myclass/func" id="form" class="form" method="post" accept-charset="utf-8">
...
<label>Username:</label>
<input type="text" id="user_id" name="user_id" />
<script type="text/javascript">
$(document).ready(function () {
$("#user_id").jqxInput({ ... });
});
</script>
...
<input type="submit" value="Login" id="loginButton" />
<script type="text/javascript">
$(document).ready(function () {
$("#loginButton").jqxButton({ ... });
});
</script>
...
</form>
...
<script>
$('#form').jqxValidator({rules: [{ input:'#user_id', rule:'required', ...}]});
$("#loginButton").click(function () {
$('#form').jqxValidator('validate');
});
$("#form").on('validationError', function () {
return false; // note: hope this will prevent the form from
// being submitted but not working
});
...
</script>
In my test, after the validation fails, it shows the error message next to the fields.
However, (I think) the form continues to be submitted.
So, right after the error message pops up, the screen gets updated to the next right away.
I add “return false” to the “validationError” event; however, it doesn’t stop the form from being submitted.
Is there anything I can do to prevent the form from being submitted when the validation fails, or am I missing anything?
Thank you!
