[ShindouParticipant]

Thanks for yout answer,but the example is not what I want.

For example,I received the following XML data:

<item code="msg">
  <item code="msgCode">
    <item code="encode"></item>
  </item>
</item>

Element:<item code=”msg”> is parent of element:<item code=”msgCode”>
And element:<item code=”msgCode”> is parent of element:<item code=”encode”>

I want to show this 3-deep-level relation(msg->msgCode->encode),

because the parent-child relation is obvious(by start tag and end tag),
so I think it’s not necessary to provide a hierarchy like:

{
  root: 'Employees',
  record: 'Employee'
}

or

{
    keyDataField: { name: 'EmployeeID' },
    parentDataField: { name: 'ReportsTo' }
}

But I still don’t know how to defines the root and record of each hiearchy level in jqxTreeGrid.

Sorry for my poor English,I find a little similar question at this forum,
hope it’s useful to make my question clear:
http://www.jqwidgets.com/community/topic/my-first-treegrid-3-level-deep-xml/

Thanks again!

[ShindouParticipant]

Thank you.It works.

[ShindouParticipant]

I have a idea:

var records = $("#treeGrid").jqxTreeGrid("getRows");

var dataFileds = new Array();

and put all treeGrid’s dataFields into dataFileds except “children”,and put “records” into dataFileds

then use JSON.stringify(records,dataFileds) to get the json I want

[Author]

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