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October 21, 2014 at 11:29 am in reply to: Input source does not work Input source does not work #61445
It returns Json data .
public JsonResult method()
{var dbResult = db.ID.ToList();
var output = from e in dbResultselect new
{
e.Asso_ID,
};return Json(output, JsonRequestBehavior.AllowGet);
}
But it is not working as it shouldOctober 21, 2014 at 10:10 am in reply to: Input source does not work Input source does not work #61439Hi Peter,
Thanks for your quick response. I would check and update. but Could you please tell me why the source is not working?Regards
sandyNow the error is Microsoft JScript runtime error: Unable to get value of the property ‘prototype’: object is null or undefined
after adding both the files I’m getting the same error again
<script src=”~/Scripts/jquery.min.js”></script>
<link href=”~/Scripts/Vendor/Others/jqx.base.css” rel=”stylesheet” />
<script src=”~/Scripts/Vendor/JQControls/jqxwindow.js”></script>
<script type=”text/javascript”>
$(document).ready(function () {
$(“#Add_New”).jqxButton({ width: ‘150’ });
$(“#Add_New”).on(‘click’, function () {
alert(“Button Clicked”) ;
});
});
<body>
<input type=”button” id=”Add_New” value=”Add”/>
</body>Hi,
I found the Solution just a few minutes before. I missed the opacity property. Thanks. And Could you please help with creating two shadows of the window?October 15, 2014 at 11:02 am in reply to: Add new input row in jqxGrid Add new input row in jqxGrid #61165Thank you
Its working Fine -
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