[greg.oMember]

Hi Peter,
Thanks! Included is the table definition… I could attach snapshots but not sure how to do that…
let me know if there is anything else that’s relevant.

Thanks again,
Greg

$(“#tblList”).jqxGrid(
{
source: source,
width: 600,
columnsresize: true,
columns: [
{ text: ‘List’, datafield: ‘list’ , width: 150 },
{ text: ‘Code’, datafield: ‘lst_OptionID’ , width: 60 },
{ text: ‘Description’, datafield: ‘lst_OptionName’ , width: 150 },
{ text: ‘Sequence’, datafield: ‘lst_OptionSequence’ , width: 90 },
{ text: ‘Lst_ID’, datafield: ‘lst_ID’ , hidden: true } ],
filterable: true,
sortable: true,
pageable: true,
autoheight: false,
pagesizeoptions: [’20’, ’50’, ‘100’,’200′,’500′],
pagesize: 20,
virtualmode: true,
rendergridrows: dtaList,
autosavestate: true,
autoloadstate: true
});

[greg.oMember]

Sorry… some more details…

jqwidgets 2.8.3
jquery 1.9.1

browser: chrome Version 26.0.1410.65

Thanks
Greg

[greg.oMember]

Thanks again, Peter. I guess what I meant was how do I set the inputValue and then get the source function to retrieve… I decided just to set the placeHolder and leave it at that … works much the same… I use a hidden input to hold the id of the foreign key table to return it to the form anyways…

Thanks
Greg

[greg.oMember]

Thanks Peter. I’ve already read that one – the fundamental problem is I want to select one value on start of the page – how do I do that?

Thanks
Greg

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