[giserniaParticipant]

Hi Dimitar,
It’s possible to have a preview of the scheduler? Or to know how will be?

thanks
Giulio

[giserniaParticipant]

RESOLVED:

this is the linkrender function:

        var linkrenderer_accounts = function (row, column, value) {
            if (value.indexOf('#') != -1) {
                value = value.substring(0, value.indexOf('#'));
            }
            href =  source.records[row].ID;
            var html = "<a href=\"?module=accounts\&applettype\=baseview\&ret_module=accounts\&ret_applettype\=listview\&record="+href+"\">"+value+"</a>";
            return html;
        };

[giserniaParticipant]

I use this function
var linkrenderer = function (row, column, value) {
if (value.indexOf(‘#’) != -1) {
value = value.substring(0, value.indexOf(‘#’));
}

var format = { target: ‘”_blank”‘ };
var html = $.jqx.dataFormat.formatlink(value, format);

return html;

and it’s ok to retrieve column data.

But id is not in the row, it’s only in the source

var source =
{
datatype: “json”,
datafields: [
{ name: ‘id’},
{ name: ‘FST_NAME’},
{ name: ‘LST_NAME’},
],

and in grid definition I have:

columns: [
{ text: ”, datafield: ‘FST_NAME’, width: 200, cellsrenderer: linkrenderer},
{ text: ”, datafield: ‘LST_NAME’, width: 180 },
]

I’d like to retrieve the id value!!

thanks
Giulio

[giserniaParticipant]

yes,
the sample is ok,
but how can I calll the field ID inside the renderer function?

thanks
Giulio

[giserniaParticipant]

RESOLVED

just put
$(“#jqxMenu”).jqxMenu({ height: 30,showTopLevelArrows: true});
$(“#BS_Logout”).css(‘float’, ‘right’);
$(“#jqxMenu”).css(‘visibility’, ‘visible’);

after setting an ID (BS_Logout) for logout

Logout\n”

[giserniaParticipant]

(where logout is on the right…)

home products services ……………………………………… logout

[Author]

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