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  • christianjavan
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    Thanks, I just did what you said and all worked perfectly, using the info you give me and the example that Dimitar wrote here: http://www.jqwidgets.com/community/topic/need-to-create-grid-columns-dynamically-from-json/ I was able to find a final solution to create dynamic tables.

    For those who might be interested, here is what I did:

    First, get the query result:
    $result = odbc_exec($idconex,$consulta) or die("Query failed(-1)");

    Stored it in an Array:

    $rawdata = array();
    	while($row = odbc_fetch_array($result))
    	{
    		$rawdata[] = $row;
    	}

    Get the array keys to dynamically add them, take in count that my keys where on the second level of the array:

    $myArray = array_keys($rawdata[0]);

    Store the data for the dataFields and colums of the table:

    $dFields = array();
    	$dCols = array();
    	foreach($myArray as $value){
    		$dFields[] = array( "name" => $value, "type" => "string"); 
    		$dCols[] = array("text" => $value, "dataField" => $value, "width" => 200);
    	}

    Encoded the arrays in the “prepare the data” part of the script:

    var dfields = <?php echo json_encode($dFields); ?>;
    var dcols = <?php echo json_encode($dCols); ?>;

    The source code:

    var source =
                {
                    localData: data,
                    dataType: "json",
                    dataFields:dfields
                    ]*/
                };
    

    And the adapter:

    $("#dataTable").jqxDataTable(
                {
                    width: 2400,
                    pageable: false,
                    source: dataAdapter,
                    altRows: true,
                    sortable: true,
                    columns: dcols
                });

    I am sure that this code can be optimized.

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