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jQuery UI Widgets Forums Grid Real KO object index when filtering data???

This topic contains 2 replies, has 2 voices, and was last updated by  Sacrifice 12 years, 3 months ago.

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  • Sacrifice
    Member

    Hi jqwidgets team, I’ve some problem with a KO jqxGrid when I’m filtering value.

    here it’s my function

                $("#deleterowbutton").on('click', function () {
    var selectedrowindex = $("#jqxgrid").jqxGrid('getselectedrowindexes');
    var rowscount = $("#jqxgrid").jqxGrid('getdatainformation').rowscount;
    selectedrowindex.sort(function(a,b){return b-a});
    if (selectedrowindex != -1) {
    for(i=0;i<selectedrowindex.length;i++)
    {
    var rowid = $('#jqxgrid').jqxGrid('getrowid', selectedrowindex[i]);
    model.items.remove(model.items()[rowid]);
    console.log("index = " + selectedrowindex[i] + " ID = " + rowid + " rowscount = " + rowscount); //used for debug
    }
    }
    $("#jqxgrid").jqxGrid('clearselection');
    $(columnCheckBox).jqxCheckBox('uncheck');
    });

    that work I’m got corrected index form grid but when I’m filtering data, all index gone wrong??

    Grid was reorder row index to 0 and reorder all shown row, that why I can’t remove correct data

    form KO model.

    example
    index data
    0 AS
    1 BD
    2 SF
    3 GD
    4 ZX

    When I’m filtering D on data index from grid will changed like this

    index data
    0 BD
    1 GD

    how I can get BD index = 1 and GD index = 3 ?????


    Peter Stoev
    Keymaster

    Hi Sacrifice,

    To delete a row from jqxGrid, use the “deleterow” method. In addition, you can pass an array of row ids to the function instead of calling the function multiple times in a loop. In addition, when you define a loop I suggest you to use for(var i…. not for(i…

    Best Regards,
    Peter Stoev

    jQWidgets Team
    http://www.jqwidgets.com


    Sacrifice
    Member

    Hi Peter Stoev,

    Thank you for advice, when I’m used a ‘deleterow’ that not made KO model change the data

    here it’s my code

    var rowid = $('#jqxgrid').jqxGrid('getrowid', selectedrowindex[i]);
    var commit = $("#jqxgrid").jqxGrid('deleterow', rowid);

    have another solution for delete a real KO data with jqxgrid filtering form??

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