How do Jqxgrid Save the state of the grid?

[kuberasamratParticipant]

In our websites, we have jqxgrid(3.6) in most of the pages in our product. There are lot of grids so it is difficult to give unique names across the product. Some of the grids have same name.

Problem Statement: grid1 has saved its state when a column is sorted. Load grid2(but of same id selector). It is sending the same sorting column as a parameter. As that column doesn’t belong this page, request fails and unable to get the data.

Because of that, load state is giving the problem.

Please let me know how to overcome that. I have pasted sample code below.

var dataAdapter = new jQuery.jqx.dataAdapter(source);

    jQuery("#gridTable").jqxGrid({
	pageable:true,
	width:'100%',
	autoheight:true,
	sortable:true,
	pagerheight:32,
	pagesizeoptions:[10,20,30],
	altrows:true,
	virtualmode:true,
	columnsresize:true,
	theme:'ui-lfx',
	columnsheight:52,
	enablebrowserselection:true,
	enablemousewheel:false,
	showpinnedcolumnbackground:false,
	columnsreorder:true,
	selectionmode:"none",
	autosavestate: true,
        editable:true,
        autorowheight:true,
        ready: function(){
   		$("#gridTable").jqxGrid('loadstate');
       		$("#gridTable").jqxGrid({source: dataAdapter});                                         
        },
        rendergridrows: function()
        {  return dataAdapter.records; },
        
        columns:[
            {text: "", datafield: "id",sortable:false, editable:false, pinned:true, resizable:false },
            {text: 'campaign_name', datafield: "camp_name", editable:false}
        ]    
    });

[Peter StoevKeymaster]

Hi kubera,

jqxGrid usually saves state automatically on some user actions like sort, filter, page change. However, it may not be good for all tasks. that’s why there’s savestate method which allows you to save a state when you wish.

Best Regards,
Peter Stoev

jQWidgets Team
http://www.jqwidgets.com

[kuberasamratParticipant]

Peter,

Even If we do manual savestate method, If we load state, the same problem arises when grid state is saved when one of the columns is sorted.

[Peter StoevKeymaster]

Hi kubera,

If you load a state and change the source as you did then you will have a problem for sure, because your Grid will be in loading state when you change its source.

Best Regards,
Peter Stoev

jQWidgets Team
http://www.jqwidgets.com

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