Hello BrentH,
Please, find below an example which shows how to get position of the window:
<!DOCTYPE html PUBLIC "-//W3C//DTD XHTML 1.0 Transitional//EN"
"http://www.w3.org/TR/xhtml1/DTD/xhtml1-transitional.dtd">
<html lang="en">
<head>
<title></title>
<link rel="stylesheet" href="../../jqwidgets/styles/jqx.base.css" type="text/css" />
<link rel="stylesheet" href="../../jqwidgets/styles/jqx.summer.css" type="text/css" />
<script type="text/javascript" src="../../scripts/jquery-1.10.2.min.js"></script>
<script type="text/javascript" src="../../jqwidgets/jqxcore.js"></script>
<script type="text/javascript" src="../../jqwidgets/jqxwindow.js"></script>
<script type="text/javascript" src="../ver3.5.0/jqwidgets/jqxbuttons.js"></script>
<script type="text/javascript">
$(document).ready(function () {
$("#jqxwindow").jqxWindow({ height: 90, width: 150, theme: 'summer' });
$("#btn").jqxButton({ theme: 'summer' });
$("#btn").on('click', function () {
var p = $("#jqxwindow");
var offset = p.offset();
alert("left: " + offset.left + ", top: " + offset.top);
});
});
</script>
</head>
<body>
<div id='content'>
<div id='jqxwindow'>
<div>Header</div>
<div>Content</div>
</div>
<input type="button" id="btn" value="Get position" />
</div>
</body>
</html>
Best Regards,
Nadezhda
jQWidgets team
http://www.jqwidgets.com/
