c.offset(…) is undefined on validate

[darkelfParticipant]

Hi;
I using to validator for check user input. But sometimes take to this error.

TypeError: c.offset(…) is undefined
…var i=a(q.input);c=a(q.input);j.push(c);h=c.offset().top;if(e>h){e=h;g=c}}d–;if… jqxvalidator.js (line 7, col 1119)

It’s often work. But sometimes (I dont know how) give error like this…

(I not sure to paste my code. Because its evaluate from your example code…)

thanks

[NadezhdaParticipant]

Hello darkelf,

Please, provide a sample which illustrates your issue.

Best Regards,
Nadezhda

jQWidgets team
http://www.jqwidgets.com/

[darkelfParticipant]

Ok. I have progress in my code.

I have two dropdown field. I need at least one field selected. I mean user must select field one, field two or field one + field two.
My code is:

{ input: ‘#field1’, message: ‘Mandotory Field!’, action: ‘keyup, blur’, rule:
function () {
if ($(‘#field1’).val() > 0 || $(‘#field2’).val() > 0) { return true; } else { return false; }
}
},
{ input: ‘#field2’, message: ‘Mandotory Field!’, action: ‘keyup, blur’, rule:
function () {
if ($(‘#field1’).val() > 0 || $(‘#field2’).val() > 0) { return true; } else { return false; }
}
},

I have’nt got any error after loading. But while using i got
TypeError: c.offset(…) is undefined
…var i=a(q.input);c=a(q.input);j.push(c);h=c.offset().top;if(e>h){e=h;g=c}}d–;if… jqxvalidator.js (line 7, col 1119)
error.
I trying to comment one block like this:

/*
{ input: ‘#field1’, message: ‘Mandotory Field!’, action: ‘keyup, blur’, rule:
function () {
if ($(‘#field1’).val() > 0 || $(‘#field2’).val() > 0) { return true; } else { return false; }
}
},
*/
{ input: ‘#field2’, message: ‘Mandotory Field!’, action: ‘keyup, blur’, rule:
function () {
if ($(‘#field1’).val() > 0 || $(‘#field2’).val() > 0) { return true; } else { return false; }
}
},
it’s work vell.
Any idea of this stuation?
thanks.

[darkelfParticipant]

Ok my mistake. L solve my problem.
L made a typo. I type field1 -> filed1

Thanks.

[Author]

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