TreeGrid How to get the parent node?

[MatcherAnyParticipant]

In the API， I did not find the current node to get the method of the parent node。

[HristoParticipant]

Hello MatcherAny,

Could you give more details, which case you want to get the parent node?
For example, if you want to get a parent, when selecting a row, you could use this approach:

$('#treeGrid').on('rowSelect', function (event) {
	var args = event.args;
	var row = args.row;
	var hasParent = !!row.parent;
	if (hasParent) {
		console.log(row.parent);
	}
});

Best Regards,
Hristo Hristov

jQWidgets team
http://www.jqwidgets.com

[MatcherAnyParticipant]

I use Google Translate

Thank you very much Hristo
Use ‘rowSelect’ to get the current row, But how to get the details of the parent node？
The use of loops is not elegant ……

var parentNode = null;
        var rows = $scope.treeGridSettings.apply('getRows');
        for (var i = 0; i < rows.length; i++) {
            var node = rows[i];
            if (selectedNode.parent == node.id) {
                parentNode = node;
            }
        }

[HristoParticipant]

Hello Matthias,

I would like to suggest you try the simple example with rowSelect event.
As the example that I mentioned before var row = args.row; – “row” is an object with “parent” property.
You could show this object in the console and will see more details.

Best Regards,
Hristo Hristov

jQWidgets team
http://www.jqwidgets.com

[Author]

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