This is a question about row update in grid.

[kimmansuParticipant]

This is a question about row update in grid.
The “updaterow” does not work in the sort state.

Is this a bug?
Please let me know how to solve this problem.

http://jsfiddle.net/tankla/pdua0qfm/1/

[kimmansuParticipant]

– jQuery version : 1.12.4
– jQWidgets version : 10.0.2
– device type(PC, Mobile) : PC
– browser name and version : Chrome 85.0.4183.83 – 64bit

– Please, provide step by step instructions on how to reproduce the reported issue and provide a small sample which demonstrates it.
* 1 step : visit jsfillde URL : http://jsfiddle.net/tankla/pdua0qfm/8/
* 2 step : select any row.
* 3 step : Click the “Update Selected Row” button.
* 4 step : You can see that the selected row does not change.

– Remove the sorting of “Last name”. then you can see that the selected row does change.

I want to know why and how this happens.

Please assist.
Thank you.

[kimmansuParticipant]

UPDATE :

visit below url plz.
http://jsfiddle.net/tankla/pdua0qfm/16/

see below gif image.
https://i.imgur.com/k73CHu5.gif

[HristoParticipant]

Hello kimmansu,

Thank you for this feedback.
I will create a work item.
It seems that these issues become from the sorting feature with the "many" value option.
I mean that you could try to use the default option if it is possible for you.

Best Regards,
Hristo Hristov

jQWidgets team
https://www.jqwidgets.com

[kimmansuParticipant]

Thank you for your answer.

I solved it as below.

     var selectedrowindex = $("#jqxgrid").jqxGrid('getselectedrowindex');
     var rowscount = $("#jqxgrid").jqxGrid('getdatainformation').rowscount;
     if (selectedrowindex >= 0 && selectedrowindex < rowscount) {
         //정렬상태에서는 updaterow가 동작하지 않음으로 상태를 저장, 정렬 초기화, 상태를 다시 불러오는 방식으로 처리하자.
                            $("#jqxgrid").jqxGrid('savestate'); //상태 저장
                            $("#jqxgrid").jqxGrid('clearfilters'); // 검색 초기화
                            $("#jqxgrid").jqxGrid('removesort'); // 정렬 초기화
     
         var id = $("#jqxgrid").jqxGrid('getrowid', selectedrowindex);
         var commit = $("#jqxgrid").jqxGrid('updaterow', id, datarow);
         //$("#jqxgrid").jqxGrid('ensurerowvisible', selectedrowindex);
         
                            $("#jqxgrid").jqxGrid('loadstate'); // 저장된 상태 로드
     }

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