Grid column details from selected row

[prabhuMember]

Hi ,

Is there a way to get column details from the selected row?

The following code gets rowindex.

var rowindex = $(gridName).jqxGrid(‘getselectedrowindex’);

Is there a similar kind of API to get column details from the row’s cell that we have selected.

Thanks,
Kishore

[DimitarParticipant]

Hello Kishore,

When you have the selected row’s index, you can use it in the method getrowdata to get the desired column information.

Best Regards,
Dimitar

jQWidgets team
http://www.jqwidgets.com/

[prabhuMember]

Hi Dimitar,

Thanks for your reply. Can you show me a sample code which does that,or a demo which can help me.

thanks,
Kishore

[prabhuMember]

Is there a way to get column name or index from the cell that we have selected,with out binding cellselect event.

Thanks,
Kishore

[DimitarParticipant]

Hi Kishore,

1) Here is a sample code:

var rowindex = $(gridName).jqxGrid(‘getselectedrowindex’);
var data = $('#jqxGrid').jqxGrid('getrowdata', rowindex);

The fields of the data object contain the column values.

2) Here is an example on the cellselect event:

$("#jqxGrid").on('cellselect', function (event) 
{
    var columnheader = $("#jqxGrid").jqxGrid('getcolumn', event.args.datafield).text;
    var rowindex = event.args.rowindex;
});

Best Regards,
Dimitar

jQWidgets team
http://www.jqwidgets.com/

[JMS786Participant]

Hi Dimitar,

I have similar problem, but when i apply your code, especially in this line

var columnheader = $("#jqxGrid").jqxGrid('getcolumn', event.args.datafield).text;

I get an error :
Uncaught TypeError: Cannot read property ‘datafield’ of undefined.

I have tried to copy the code, but the different is i use the grid as an input tool, therefore my grid does not have source:dataAdapter.

Do you think the absence of source:dataAdapter is the main problem or that should be no problem?

If no problem how do I fix the ‘datafield’ error.

Thanks,
JMS

[Author]

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