addrow

[abasanParticipant]

hi

I have one problem

how can add new row at first of grid rows when call addrow method

I use grid with following option

virtualmode: true,
pageable: true,

[StanislavParticipant]

Hello abasan,

You need to call the ‘addrow’ method and give it the parameters it needs.
I suggest taking a look at our API.
You will need to add the desired position in the example.

Best Regards,
Stanislav

jQWidgets Team
http://www.jqwidgets.com/

[iroshi7e7Participant]

I have add a row where user select row,
this is my code,( I provide JQX menu)

if ($.trim($(args).text()) == “Insert Row”) {
debugger;
var args = event.args;
var selectedRowindex = $(“#jqxBoqgrid”).jqxGrid(‘getselectedrowindex’);
var DestinationRowIndex = selectedRowindex + 1;
$(‘#jqxBoqgrid’).jqxGrid(‘addrow’, selectedRowindex, {}, DestinationRowIndex);
}

I can add row any place, but when I edit this row, next row also replaced , I have several drop downs on row and when change these rows only automatically replaced next row record)

( …………..
geteditorvalue: function (row, cellvalue, editor) {
var unitItem = editor.jqxDropDownList(“getSelectedItem”);
return unitItem.label;
)

I am really appreciated if you can help me to solve this issue. Client wants to add row anywhere to grid and I should keep a sequence when print report

[abasanParticipant]

hello iroshi7e7

I think you pass row id in correct

var value = $('#jqxGrid').jqxGrid('addrow', rowid, newdata,rowPosition);
@param row id. Pass null, if you want the new id to be auto-generated or pass a row id.
@param row data. The expected value is a JSON Object.

if you pass selectedRowindex for new row id it replace selectedRow
try pass null or row id that is not used before.

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